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4.9x^2-29x+14=0
a = 4.9; b = -29; c = +14;
Δ = b2-4ac
Δ = -292-4·4.9·14
Δ = 566.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{566.6}}{2*4.9}=\frac{29-\sqrt{566.6}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{566.6}}{2*4.9}=\frac{29+\sqrt{566.6}}{9.8} $
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